0=2w^2-3w-104

Solution for 0=2w^2-3w-104 equation:

0=2w^2-3w-104

We move all terms to the left:

0-(2w^2-3w-104)=0

We add all the numbers together, and all the variables

-(2w^2-3w-104)=0

We get rid of parentheses

-2w^2+3w+104=0

a = -2; b = 3; c = +104;
Δ = b2-4ac
Δ = 32-4·(-2)·104
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-29}{2*-2}=\frac{-32}{-4}
=+8
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+29}{2*-2}=\frac{26}{-4}
=-6+1/2
$